fix(api-server): handle QQ Music API export differences across versions

The @sansenjian/qq-music-api module's export structure varies between
versions (2.2.10 vs 2.2.11+). Add fallback chain to find the Koa app:
try candidate.listen first, then candidate.default.listen.

Also resolve leftover merge conflict marker in instance.ts.

Co-Authored-By: Claude Opus 4.6 (1M context) <noreply@anthropic.com>

src/bot/instance.ts

@@ -61,11 +61,9 @@ export class BotInstance extends EventEmitter {
   private disconnectEmitted = false;
   private voteSkipUsers = new Set<string>();
   private isAdvancing = false;
-<<<<<<< HEAD
   private idleTimer: ReturnType<typeof setTimeout> | null = null;
   private channelUserCount = 0;
   private profileManager: BotProfileManager;
->>>>>>> origin/main
 
   constructor(options: BotInstanceOptions) {
     super();

src/music/api-server.ts

@@ -76,7 +76,14 @@ export function createApiServerManager(
           );
         } else {
           const qqModule = (await import("@sansenjian/qq-music-api")) as any;
-          const koaApp = qqModule.default ?? qqModule;
+          // The module's export structure varies between versions:
+          //   2.2.11+: default → Koa app (has .listen)
+          //   2.2.10:  default → wrapper object whose .default is the Koa app
+          //   older:   module itself may be the Koa app
+          const candidate = qqModule.default ?? qqModule;
+          const koaApp = typeof candidate.listen === "function"
+            ? candidate
+            : candidate.default ?? null;
           if (koaApp && typeof koaApp.listen === "function") {
             qqMusicServer = await new Promise<Server>((resolve, reject) => {
               const srv = koaApp.listen(options.qqMusicPort, "127.0.0.1", () =>